So we know the device is voltage driven so why do we need \$R_\$ charges back up which are made longer due to the inclusion of the load resistance in the charge path. Simulate this circuit – Schematic created using CircuitLab NOTE: I am only going to illustrate N-Channel devices here, but P-Channel works by the same mechanisms. Let's look at your typical MOSFET circuit. However, how the gate actually works is probably one of the least understood characteristics for many would be designers. The fact that they are voltage driven and that, when on, they have very low resistances make them the device of choice for many applications. MOSFETs are remarkable devices which provide many benefits when driving various loads. I would advise to put a resistor footprint just in case, and start with a 0R jumper. This is a bit of a band-aid, a tight layout is preferable. A resistor will dampen the oscillations, at the cost of slower switching. This adds inductance in the gate which can cause the MOSFET to osillate.
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